2592-r^2-6r=0

Solution for 2592-r^2-6r=0 equation:

2592-r^2-6r=0

We add all the numbers together, and all the variables

-1r^2-6r+2592=0

a = -1; b = -6; c = +2592;
Δ = b2-4ac
Δ = -62-4·(-1)·2592
Δ = 10404
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10404}=102$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-102}{2*-1}=\frac{-96}{-2}
=+48
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+102}{2*-1}=\frac{108}{-2}
=-54
$